C Program Language (Skip Count by 3 and 5)

I was asked by my teacher to create a program using while repetition statement skip counting by 3 and skip counting by 5. Thinking how to create it I was puzzled first on how to accomplish my task. To create the program I must think first the different ways on how to solve the program and I figured out the solution. 

Now check this program skip counting by 3.

Here is the codes of the program skip counting by 3.

#include<stdio.h>
#include<conio.h>

int main()

{
int x;

x=3;

while (x <= 48)
{
if(x == 3){
x=x-2;
printf("%d   ",x);
}
else{
x = x + 3;
printf("%d   ",x-1);
}}
getch();
}

Now check the program below using the skip counting by 5. I used the do while repetition statement in creating the program.

The codes for skip counting by 5.

#include<stdio.h>
#include<conio.h>

main()
{
int x;

x=5;
do
{
if(x==5){
x=x-4;
printf("%d   ",x);}
else{x=x+5;
printf("%d   ",x-1);
}
}
while (x<=50);

getch();

}

The repetition statement is very important in programming it is all due because it is being used by a programmers to loop the program simultaneously. Hope this program can help you on how to used the repetition statement.